Question

express sin5x-sin4x as a product of trigonometric function

Answer 1

sin5x-sin4x
so
⇒sinx
and 
sinx can also be written as sinθ where
sin is function
and θ is angle

Answer 2

Answer:  $2cos (\frac{9x}{2}) sin (\frac{x}{2})$

Step-by-step explanation:

Since,

$sin a - sin b = 2 cos(\frac{a+b}{2})sin(\frac{a-b}{2})$

Here, the given expression is,

$sin 5x - sin 4x$

By the above formula,

$=2 cos(\frac{5x+4x}{2})sin(\frac{5x-4x}{2})$

$2cos (\frac{9x}{2}) sin (\frac{x}{2})$

Which is the required product of the trigonometric functions.