Question

If x=3 is one root of quadratic equation x2-2kx-6=0, then find the value of k

Answer 1

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Answer 2

Let p(x) = x^2 – 2kx – 6 = 0

x = 3 is one root of the quadratic equation

Remainder = p(3) = 0

p(3) = 0

(3)^2 – 2k(3) – 6 = 0

– 6k = - 3

k =  6/3

k = 1/2