Math, asked by ganeshlanghi1807, 5 months ago

if x=3 is one root of the equation kx2-10x+3=0 find value of k

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Answered by riyabante2005

9

Step-by-step explanation:

kx²-10x+3=0

k(3)²-10×3+3=0

9k²-30+3=0

9k²-27=0

9k²=27

k²=27/9

k²=3

taking square root on both sides,

k=√3

Answered by wsriraj10

12

Answer:

ka²-10x+3 = 0

K(3)²-10(3)+3=0

k2 ak-30+3=0

9k-27=0

9k=27

K=3

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