if x=3 is one root of the equation kx2-10x+3=0 find value of k
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Answered by
9
Step-by-step explanation:
kx²-10x+3=0
k(3)²-10×3+3=0
9k²-30+3=0
9k²-27=0
9k²=27
k²=27/9
k²=3
taking square root on both sides,
k=√3
Answered by
12
Answer:
ka²-10x+3 = 0
K(3)²-10(3)+3=0
k2 ak-30+3=0
9k-27=0
9k=27
K=3
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