Question

if x=3 is one root of the quadratic equation x^2-2kx-6, then find the value of k.​

Answer 1

Answer:

k=¹/₂

Step-by-step explanation:

x²-2kx-6=0

∵ x=3 is one root

∴ 3² - 2×k×3 - 6=0

9 - 6k - 6=0

6k + 3 = 0

-6k = -3

k=¹/₂

Answer 2

Answer:

$x = 3 \\ and \: ur \: equation \:is \: x}^2 - 2kx -6 \\ put \: x = 3 \: in \: the \: equation \\ {3}^{2} - 2 \times 3k - 6 \\ 9 - 6k - 6 \\ - 6k = 3 \\ k = 3 \div - 6 \\ k = - 1 \div 2 \\ = - 0.5$

hope it help you...

Mark me as a brainlist plzz