if x=3 is one root of the quadratic equation x^-2kx-6=0.then find the value of k.
Answers
Answered by
109
Heya..!!!!
given that:-
it's one of the zeroes
X = 3
now put the value of x in Quadratic Equation,
X² - 2kx - 6 = 0
⇒(3)² - 2×k×(3) - 6 = 0
⇒9 - 6k - 6 = 0
⇒3 - 6k = 0
⇒6k = 3
⇒k = 3/6
⇒k = 1/2
HOPE it's help you
given that:-
it's one of the zeroes
X = 3
now put the value of x in Quadratic Equation,
X² - 2kx - 6 = 0
⇒(3)² - 2×k×(3) - 6 = 0
⇒9 - 6k - 6 = 0
⇒3 - 6k = 0
⇒6k = 3
⇒k = 3/6
⇒k = 1/2
HOPE it's help you
Answered by
41
Solution :-
Given that x = 3, which is one root of the quadratic equation x² - 2kx - 6 = 0
Substituting the value of x = 3 in the given quadratic equation.
⇒ (3)² - 2k*3 - 6 = 0
⇒ 9 - 6k - 6 = 0
⇒ - 6k = 6 - 9
⇒ - 6k = - 3
⇒ 6k = 3
⇒ k = 3/6
⇒ k = 1/2
So, the value of k is 1/2
Answer.
Given that x = 3, which is one root of the quadratic equation x² - 2kx - 6 = 0
Substituting the value of x = 3 in the given quadratic equation.
⇒ (3)² - 2k*3 - 6 = 0
⇒ 9 - 6k - 6 = 0
⇒ - 6k = 6 - 9
⇒ - 6k = - 3
⇒ 6k = 3
⇒ k = 3/6
⇒ k = 1/2
So, the value of k is 1/2
Answer.
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