Question

If x=3 is one root of the quadratic equation x square -2kx -6=0 then find the value of k

Answer 1

${x}^{2} - 2kx - 6 = 0 \\ x = 3 \\ {3 }^{2} - 2k.3 - 6 = 0 \\ 9 - 6k - 6 = 0 \\ 3 - 6k = 0 \\ 6k = 3 \\ k = \frac{3}{6} \\ k = \frac{1}{2}$

Answer 2

find sum of roots
then product of roots ..

then put one roots in it .. and by solving u will get the abser