If x =3 is one root of the quadratic equation x²-2kr-6=0 find the value of k
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If x =3 is one root of the quadratic equation x² - 2 kx - 6=0 find the value of k.
Then, p(x) = x² - 2 kx - 6
p(3) = (3)² - 2 k(3) - 6
0 = 9 - 6 k - 6
6 k = 3
k = 1/2
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☺☺☺ Hope this Helps ☺☺☺
If x =3 is one root of the quadratic equation x² - 2 kx - 6=0 find the value of k.
Then, p(x) = x² - 2 kx - 6
p(3) = (3)² - 2 k(3) - 6
0 = 9 - 6 k - 6
6 k = 3
k = 1/2
_________________________________________________________
☺☺☺ Hope this Helps ☺☺☺
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