if x=3 is one root of the quadratic equation x2-2kx-6=0,then find the value of k
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Heya !!!
X = 3
P(X) = X² - 2KX -6
P(3) = (3)² - 2 × K × 3 -6
=> 9 - 6K -6 = 0
=> -6K +3 = 0
=> -6K = -3
=> K = 3/6 = 1/2
★ HOPE IT WILL HELP YOU ★
X = 3
P(X) = X² - 2KX -6
P(3) = (3)² - 2 × K × 3 -6
=> 9 - 6K -6 = 0
=> -6K +3 = 0
=> -6K = -3
=> K = 3/6 = 1/2
★ HOPE IT WILL HELP YOU ★
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