if x =3 is one root of the quadratic equation x2-2kx-6=0,then find the value of k.
Answers
Answered by
4
put x=3 in x2-2kx-6=0
(3)2-2k(3)-6=0
9-6k-6=0
3-6k=0
-6k=-3
6k=3
k=3÷6
k=1/2
(3)2-2k(3)-6=0
9-6k-6=0
3-6k=0
-6k=-3
6k=3
k=3÷6
k=1/2
Answered by
0
x^2-2kx-6 = 0.
We know that 3 is a root of x
x=3
Putting x=3 in eqn
(3)^2-2(k)(x)-6=0
9-6k-6=0
6k=6-9
6k=-3
k=-3/6
k= -1/2
We know that 3 is a root of x
x=3
Putting x=3 in eqn
(3)^2-2(k)(x)-6=0
9-6k-6=0
6k=6-9
6k=-3
k=-3/6
k= -1/2
Attachments:
Similar questions