If x=3 is one root of the quadratic of x2-2kr-6=0.then find the value of k
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Answered by
1
9-6k-6=0
3-6k=0
6k=3
K=1/2
3-6k=0
6k=3
K=1/2
Answered by
0
♧♧HERE IS YOUR ANSWER♧♧
Since x = 3 is a root of x² - 2kx - 6 = 0, x = 3 satisfies the equation.
So, the value of k is 1/2.
3² - (2×k×3) - 6 = 0
or, 9 - 6k - 6 = 0
or, 6k = 3
or, k = 1/2
So the value of k = 1/2
♧♧HOPE IT HELPS YOU♧♧
Since x = 3 is a root of x² - 2kx - 6 = 0, x = 3 satisfies the equation.
So, the value of k is 1/2.
3² - (2×k×3) - 6 = 0
or, 9 - 6k - 6 = 0
or, 6k = 3
or, k = 1/2
So the value of k = 1/2
♧♧HOPE IT HELPS YOU♧♧
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