Question

If x=3 is one root of the quadric equation x^2-2kx-6=0 then find the value of k

Answer 1

So 3^2-2*3*k-6=0
=>9-6*k-6=0
=>9-6-6k=0
=>3-6k=0
=>-6k=0-3
=>k=-3/-6
=>k=1/2(answer)
Hope it helps you!!
Please please Mark it as brainlist!

Answer 2

Answer:

The value of k is $k=\frac{1}{2}$

Step-by-step explanation:

Given : Quadratic equation $x^2-2kx-6=0$

One root of the given quadratic equation is x=3

To find : The value of k

Solution :

To find the value of k we put the value of x in the given equation as it the root bit satisfy the equation.

$x^2-2kx-6=0$

Put x=3

$(3)^2-2k(3)-6=0$

$9-6k-6=0$

$3-6k=0$

$6k=3$

$k=\frac{3}{6}$

$k=\frac{1}{2}$

Therefore, The value of k is $k=\frac{1}{2}$