If x=3 is onr root of the eq.x square -2kx-6=0 then find value of k
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Answered by
1
Substitute value of x in the equation
-2k(3)-6=0
-6k-6=0
-6k=6
k= -1
Therefore the value of k= -1.
-2k(3)-6=0
-6k-6=0
-6k=6
k= -1
Therefore the value of k= -1.
Answered by
0
k value is 1/2.
x² -2kx-6=0
(3)²-2(k)(3)-6=0
9-6k-6=0
9-6=6k
3=6k
k=3/6
k=1/2
x² -2kx-6=0
(3)²-2(k)(3)-6=0
9-6k-6=0
9-6=6k
3=6k
k=3/6
k=1/2
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