if x= 3 is root of the quadratic equation x² -2k -6 = 0 then find the value of k
Answers
Answered by
1
x^2 -2k -6 = 0
putting the value of x
3^2 - 2k = 6
9 -2k = 6
-2k = 6-9
-2k = -3
2k = 3
k = 3/2
i hope this will help you
-by ABHAY
putting the value of x
3^2 - 2k = 6
9 -2k = 6
-2k = 6-9
-2k = -3
2k = 3
k = 3/2
i hope this will help you
-by ABHAY
ojaspuri17p690yt:
thank you so much brother ❤️
Answered by
0
p(x)=x2 -2k -6
(x=3) is a root of p(x)
Therefore,
p(3)=(3)2 -2k -6=0
9 -2k -6=0
3 -2k=0
3=2k
k=3/2
Here it is!!!!
(x=3) is a root of p(x)
Therefore,
p(3)=(3)2 -2k -6=0
9 -2k -6=0
3 -2k=0
3=2k
k=3/2
Here it is!!!!
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