Math, asked by manyata3, 1 year ago

answer to this question.........answer

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Answered by 16Devesh16
1
hope it helps you ......
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Answered by vijay31504
1
Sn=n/2×(2a+(n-1)d)
S7=7/2×(2a+6d)
49×2/7=2a+6d
14=2(a+3d)
a+3d=7 - 1

S17=17/2×(2a+16d)
289×2/17=2(a+8d)
17×2/2=a+8d
a+8d=17 - 2

subtracting 1&2
3d-8d=7-17
-5d=-10
d=-10/-5
d=2

substitute d=2 in 1
a+3×2=7
a=7-6
a=1

Sn=n/2×(2a+(n-1)d)
=n/2(2×1+2n-2)
=n/2×2n
=n^2

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