one of the two digits of a two digit number is the three times the other digit.if you interchange the digits of this two-digit number and add the resulting number to the original number,you get 88.what is the original number?
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Let the digit in units place = x
That means the digit in tens place will be 3x (ATQ)
The number is 10* 3x + x = 31x
Now, the digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number will be 10x + 3x = 13x
Also given that sum of these two numbers = 88
So, 31x + 13x = 88
⇒44x = 88
⇒x = 2
Then, 3x = 6
Therefore the required number is 62
That means the digit in tens place will be 3x (ATQ)
The number is 10* 3x + x = 31x
Now, the digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number will be 10x + 3x = 13x
Also given that sum of these two numbers = 88
So, 31x + 13x = 88
⇒44x = 88
⇒x = 2
Then, 3x = 6
Therefore the required number is 62
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