Question

if x = 3 one root of quadratic equation x squre -2kx -6 =o then find the value of k

Answer 1

Hello friend your answer is
x=3
then it put in equation
x²-2kx-6=0
3²-2×k×3-6=0
9-6k-6=0
3-6k=0
-6k=-3
6k=3
k=3/6=1/2

Answer 2

Answer:

$Value \: of \: k = \frac{1}{2}$

Step-by-step explanation:

$Given ,\\quadratic \: equation: \\\: x^{2}-2kx-6=0,\:</p><p>and \: \\one \: root \: x = 3$

$Now, \\Substitute \: x = 3 \: in \: equation\\ \:,we \: get$

$3^{2}-2k\times 3 -6 =0$

$\implies 9-6k-6=0$

$\implies 3-6k=0$

$\implies -6k = -3$

$\implies k = \frac{-3}{-6}\\\implies k=\frac{1}{2}$

Therefore,

$Value \: of \: k = \frac{1}{2}$

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