If x=3 one root of the quadratic equation x-2kx-6=0, then find the value of k
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put the value of x in eq x-2kx-6 = 0
then, 3-2k(3) -6 = 0
3-6k-6=0
-6k= 6-3
-6k = 3
k=-3/6
k=-1/2
hope it helps
then, 3-2k(3) -6 = 0
3-6k-6=0
-6k= 6-3
-6k = 3
k=-3/6
k=-1/2
hope it helps
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