if x = 3 one root of the quadratic equation X square - 2 k - 6 = 0 then find the value of k
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Hey !!
X = 3
P ( x ) = X² - 2K - 6
P (3) = (3)² - 2 K - 6
=> 9 - 2K - 6 = 0
=> -2K = -3
=> K = 3/2
X = 3
P ( x ) = X² - 2K - 6
P (3) = (3)² - 2 K - 6
=> 9 - 2K - 6 = 0
=> -2K = -3
=> K = 3/2
Kiru6:
Hi
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