Question

If x = 3 -- root 13 divide by 2 then what is the value of x square + 1 divide by x square

Answer 1

Answer:

$x = 3 \sqrt{13} \div 2$

Then,

${x}^{2} + 1 \div {x}^{2} =$

$({3 \sqrt{13 } \div 2)} ^{2} + 1 \div ({3 \sqrt{13} \div 2)}^{2}$

$(9 \times 13 \div 4 ) + 1 \div (9 \times 13 \div 4)$

$(117 \div 4) + 1 \div (117 \div 4)$

$(117 + 4) \div 4 \div (117 \div 4)$

$(121 \div 4) \div (117 \div 4)$

$(121 \div 4) \times (4 \div 117)$

$then \: \: 121 \div 117 \:$

$answer$