Question

if x = 3 + root8 , find the value of [ x 2 + 1/x 2 ] ?

Answer 1

x=3+√8
=> 1/x=1/3+√8 × 3-√8/3-√8 = 3-√8/(3)^2-(√8)^2
=3-√8/9-8 = 3-√8/1 = 3-√8

Now, (x^2 + 1/x^2) = [(3+√8)^2 + (3-√8)^2]
=[(9+8+6√8) + (9+8-6√8)]
=(17+6√8 + 17-6√8)
=34

Answer 2

Answer:

34

Step-by-step explanation:

Given, x=3+root 8

x=3+√8

= 1/x=1/3+√8 × 3-√8/3-√8 = 3-√8/(3)^2-(√8)^2

=3-√8/9-8 = 3-√8/1 = 3-√8

=(x^2 + 1/x^2) = [(3+√8)^2 + (3-√8)^2]

=[(9+8+6√8) + (9+8-6√8)]

=(17+6√8 + 17-6√8)

=34

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