If x= 3 sin theta + 4 cos theta and y = 3 cos theta - 4 sin theta then prove that x^2+y^2=25
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Answered by
19
Step-by-step explanation:
let theta be 'a'
x=3sin(a)+4cos(a)
y=3cos(a)-4sin(a)
x^2+y^2= {3sin(a)+ 4cos(a)}^2+ {3cos(a)-4sin(a)}^2
=>>9sin^2(a) +16cos^2(a) +24sin(a)cos(a)+ 9cos^2(a) + 16sin^2(a)-24sin(a)cos(a)
=>>>9{sin^2(a)+ cos^2(a)}+ 16{sin^2(a) +cos^2(a)}
=>>>9+16. { sin^2(a)+cos^2(a) =1}
=>>>>25
Answered by
8
Answer:
hope it is helpful
Step-by-step explanation:
this is clear explanation
have a grt day ☺
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