Question

if x^3+x^2-ax+b is divisible by (x^2-x),write the value of a and b​

Answer 1

Answer:

a = 2 and b = 0

Step-by-step explanation:

factors of x^2 - x are 0,1

putting the value 0 in the equation x^3 + x^2 -ax + b we get b= 0

putting the value 1 in the equation x^3 + x^2 -ax + b we get 2-ax+b=0

As b = 0

a = 2

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