Question

if x =3, y =2 then find the value of (x-y) (x² + xy + y^2)​

Answer 1

Step-by-step explanation:

(3 - 2) × (3^2 + 3 × 2 + 2^2)

1 × (9 + 6 + 4)

1 × 15 + 4

1 × 19 = 19

Answer) 19

Answer 2

Answer:

19

Solution:

$x = 3 \\ y = 2$

We have to find the value of

$(x - y)( {x}^{2} + xy + {y}^{2} )$

So,putting the values of x and y.

$(3 - 2)( {3}^{2} + 3 \times 2 + {2}^{2} ) \\ 1 \times (9 + 6 + 4) \\ 1 \times 19 \\ 19$

So,19 is the answer.