if x^31+31 is divided by (x+1) then find the remainder
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Answered by
195
Given p(x)= x³¹+31
And g(x)=x+1
Using remainder theorem, we have x=-1 (from g(x))
So, putting x=-1 in p(x), we have
(-1)³¹+31= -1+31=30 is the remainder
When a negative integer is raised to an odd power, the answer is negative but when it is raised to an even power, the answer is positive.
And g(x)=x+1
Using remainder theorem, we have x=-1 (from g(x))
So, putting x=-1 in p(x), we have
(-1)³¹+31= -1+31=30 is the remainder
When a negative integer is raised to an odd power, the answer is negative but when it is raised to an even power, the answer is positive.
Answered by
77
Ello here is ur answer
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