Question

if x=32underroot2 find value x+1/x

Answer 1

Your answer is --

Given,

$x = 32 \sqrt{2}$

So,
$\frac{1}{ x } = \frac{1}{32 \sqrt{2} }$


Therefore ,

$x + \frac{1}{x} = 32 \sqrt{2} + \frac{1}{32 \sqrt{2} } \\ \\ \\ = \frac{2049}{32 \sqrt{2} } \\ \\ = \frac{2049 \sqrt{2} }{64}$
【 Hope it helps you 】

Answer 2

Given,
X=32√2
:.1/x=1/32√2
1/x=32√2/2048
:.x+1/x
=32√2+32√2/2048
=(65536√2+32√2)/2048
=65568√2/2048
=2049√2/64
(ÆÑẞWĒR)

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