if x=3is one roots of the quadrante of x²-2k-6=0 then find tha value of k
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Answered by
1
x² -2k -6 =0
3² -2k =6
9-2k =6
9-6 = 2k
3=2k
3/2 =k
I hope this will help you
-by ABHAY
3² -2k =6
9-2k =6
9-6 = 2k
3=2k
3/2 =k
I hope this will help you
-by ABHAY
sachin1233:
thanks bro
Answered by
1
X=3 will satisfy equation
=> 9-2k-6 = 0
=> k =1.5
=> 9-2k-6 = 0
=> k =1.5
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