Question

If x = 3t and y = t^2 - 4t + 1, find dydx

Answer 1

Answer:

(2x-12)/9

Step-by-step explanation:

Differentiate Y with respect to X

dy/dx = d(t^2 - 4t +1) /dx

put value of t = x/3

dy/dx = d (x/3)^2/dx - d(4×x/3)/dx + d(1)/dx

dy/dx = 2x/9 -4/3 +0

dy/dx = (2x -12)/9