if x-3y-5=0 is the perpendicular bisector of AB and A(-1,-3) then find B
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Step-by-step explanation:
Let the coordinates of B be
B
(
p
,
q
)
and coordinates of
A
being
(
−
1
,
−
3
)
and slope of
B
A
is
q
+
3
p
+
1
and mid point of
B
A
is
(
p
−
1
2
,
q
−
3
2
)
. Note that this will be point of intersection of
B
A
with its perpendicular bisector.
as
B
A
is perpendicular to its perpendicular bisector
x
−
3
y
−
5
=
0
and hence product of their slope should be
−
1
as
x
−
3
y
−
5
=
0
in slope-intercept form is
y
=
1
3
x
−
5
3
(1), its slope is
1
3
and hence slope of
B
A
is
−
1
1
3
=
−
3
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