If ( x+3y)= 6 and xy=2 ,find the value of ( x³+27y³)
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(x+3y)= 6 and xy=2
( x³+27y³)
=( x³+(3y)³)
=(x+3y)(x²-xy+y²)
=(6)(x²+y²-2)
=6x²+6y²-12
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