Math, asked by sadhanagc, 8 months ago

If x=4−√15, find the value of x^2+1/x^2

Answers

Answered by unknon51
6

Answer:

x = 4 - √15

x² = 16 + 15 - 8√15 = 31 - 8√15

1/x² = 1/31 - 8√15 = (31+8√15) / 961-960 = 31+8√15

x² + 1/x² = 62

Step-by-step explanation:

Answered by AKStark
0

Answer:

x = 4 -  \sqrt{15}  \\  \\  \frac{1}{x}  = 4 +  \sqrt{5}

 {x}^{2}  =  {4}^{2}    + { \sqrt{5} }^{2}   - 8 \sqrt{5}  \\  \\  = 21 - 8 \sqrt{5}

 \frac{1}{ {x}^{2} }  = 21 + 8 \sqrt{5}

NOW X^2 +1/X^2:

21 + 8 \sqrt{5}  + 21 - 8 \sqrt{5}  \\  \\  = 42

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