Math, asked by sassybabe, 10 months ago

If x = 4 + 2√3 find the value of √x + 1/√x

Answers

Answered by BrainlyPopularman
1

Answer:

 {( \sqrt{x}  +  \frac{1}{ \sqrt{x} }) }^{2}  = x +  \frac{1}{x}  + 2 \\  \\  = 4 + 2 \sqrt{3}  +  \frac{1}{4 + 2 \sqrt{3} }  + 2  \\  =  \frac{16 + 12 + 16 \sqrt{3}  + 1}{4 + 2 \sqrt{3} }  + 2 \\  \\  =  \frac{29 + 16 \sqrt{3} }{4 + 2 \sqrt{3} }  + 2 =  \frac{37 + 20 \sqrt{3} }{4 + 2 \sqrt{3} }  \\  \\  \sqrt{x }  +  \frac{1}{ \sqrt{x} }  =  \sqrt{ \frac{37 + 20 \sqrt{3} }{4 + 2 \sqrt{3} } }

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