IF X^4- 2X^3 + 3X^2- AX +B IS A POLYNOMIAL SUCH THAT WHEN IT IS DIVIDED BY X-1 AND X+1 THE REMAINDERS ARE 5 AND 19 RESPECTIVELY. FIND A AND B DETERMINE THE REMAINDER WHEN F(X) IS DIVIDED BY X-2
Answers
Answered by
17
the value of A= -7-4x/x
Answered by
55
Answer : a = 5, b = 8 & Remainder is 10.
Step - by - step explanation :
p(x) = x⁴ - 2x³ + 3x² - ax + b
Keeping value of x = + 1 and x = - 1
p(1) = (1)⁴ - 2(1)³ + 3(1)² - a(1) + b
5 = 1 - 2 + 3 - a + b
5 = 2 - a + b
3 = - a + b _(i)
Similarly, g(x) = x⁴ - 2x³ + 3x² - ax + b
g(-1) = (-1)⁴ - 2(-1)³ + 3(-1)² - a(-1) + b
19 = 1 + 2 + 3 + a + b
13 = a + b _(ii)
By adding (i) and (ii) equation,
16 = 2b
b = 16/2 = 8
Keeping value of b at eq (ii)
13 = a + 8
13 - 8 = 5 = a
So, polynomial is x⁴ - 2x³ + 3x² - (5)x + 8
= x⁴ - 2x³ + 3x² - 5x + 8
Keeping value of x as 2,
f(2) = 2⁴ - 2(2)³ + 3(2)² - 5(2) + 8
= 12 - 10 + 8
= 10
Step - by - step explanation :
p(x) = x⁴ - 2x³ + 3x² - ax + b
Keeping value of x = + 1 and x = - 1
p(1) = (1)⁴ - 2(1)³ + 3(1)² - a(1) + b
5 = 1 - 2 + 3 - a + b
5 = 2 - a + b
3 = - a + b _(i)
Similarly, g(x) = x⁴ - 2x³ + 3x² - ax + b
g(-1) = (-1)⁴ - 2(-1)³ + 3(-1)² - a(-1) + b
19 = 1 + 2 + 3 + a + b
13 = a + b _(ii)
By adding (i) and (ii) equation,
16 = 2b
b = 16/2 = 8
Keeping value of b at eq (ii)
13 = a + 8
13 - 8 = 5 = a
So, polynomial is x⁴ - 2x³ + 3x² - (5)x + 8
= x⁴ - 2x³ + 3x² - 5x + 8
Keeping value of x as 2,
f(2) = 2⁴ - 2(2)³ + 3(2)² - 5(2) + 8
= 12 - 10 + 8
= 10
Prakhar2908:
Excellent Answer sis' !
Similar questions
Math,
6 months ago
Economy,
6 months ago
Math,
1 year ago
Math,
1 year ago
India Languages,
1 year ago
Social Sciences,
1 year ago