If x =4/3 is a root of the polynomial f (x)= 6x^3-11x^2 +kx-20. Find the value of k
Answers
Answered by
353
On putting the value of root of a polynomial into that polynomial we get 0
so, 6(4/3)^3-11(4/3)^2+k4/3-20=0
→128/9-176/9+k4/3 -20=0
→-48/9+k4/3 -20=0
→-16/3+k4/3 -20=0
→(4k-16)/3=20
→4k-16=60
→4k=76
→k=19
so, 6(4/3)^3-11(4/3)^2+k4/3-20=0
→128/9-176/9+k4/3 -20=0
→-48/9+k4/3 -20=0
→-16/3+k4/3 -20=0
→(4k-16)/3=20
→4k-16=60
→4k=76
→k=19
Answered by
189
Hope it may help u in the image
Attachments:
Similar questions