If x = 4/3 is a zero of the polynomial f(x) = 6x^3 + 11x^2 + kx - 20,find the value of k
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Step-by-step explanation:
x=4/3
p(x)=6x^3+11x^2+kx-20
p(4/3)=6(4/3)^3+ 11(4/3)^2+k(4/3)-20
=(6×64/27)+(11×16/9)+4k/3-20
=( 128/9) +(176/9)+4k/3-20
=128+176+12k-180/9
=125+12k/9=0
=125+12k=0
=12k= -125
=k= -125/12
hope it helps u!!!! :)))
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