Question

If x=4√5 find value of ( x+1÷x) whole square

Answer 1

Answer:

$( 4 \sqrt{5} + \frac{1}{4 \sqrt{5} } ) {}^{2}$

$(\frac{80 + 1}{4 \sqrt{5} } ) {}^{2}$

$(\frac{81}{4 \sqrt{5} } ) {}^{2}$

$\frac{6561}{80}$

Answer 2

Answer:

Given that :-

x = 4 - root5

Therefore,

1/x = 1/4 - root5

Or,

1/x = 4+root 5/ 16 - 5

1/x = 4 + root 5 / 11

Now,

We have to find the value of :-

(x + 1/x )^2 - (x - 1/x)^2

We can see here the formula of

a^2 - b^2

So,

This can be re written as

(a + b )(a - b )

So,

Putting this value only in our question format

This becomes

(x + 1/x)^2 - (x - 1/x)^2 = (x+1/x + x -1/x) (x + 1/x -x + 1/x)

This then further becomes(after simplification ) :-

= ( 2x)(2.1/x)

= 2x* 2/x = 4

Also, it can be solved by putting the values.

But, this is the easiest process to get the direct answer.

Plz mark brainliest ❤️

Step-by-step explanation: