if X=4,y=2 and z=5 then find
(i)2x-z
(ii) 44²x-3y²z-8xz
(iii)2xy-yz+y
(please answer step - by - step )
Answers
Answered by
1
Answer:
as x= 4 , y=2 , and z=5
so ,
putting the value In (i) part.
2x-z
= 2×4-5
= 8-5
= 3
Answered by
3
Answer:
hope this helps u
Step-by-step explanation:
2x-z
we sub-suit the values
2*4-5
8-5
=3
2x-z= 3
44^2x-3y^2z-8xz
44^2*4- 3*2*2-5- 8*4*5
1936*4-12-5-160
7744 - 7- 160
44^2x-3y^2z-8xz= 7744-167= 7577
2xy-yz+y
2*4*2-2*5+2
16-10+2
2xy-yz+y= 18 -10 = 8
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