Question

If (x, 40, 41) is a Pythagorean triple, what is the value of x?

Answer 1

Answer:

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Answer 2

Given :-

→ Pythagorean triple = x, 40, 41

To Find :-

→ Value of x

Understanding the question,

• A Pythagorean triple consists of three positive integers a, b, and c, such that a² + b² = c²
• So, the equation we would get is x² + 40² = 41²

Solution :-

$\text{ x^{2} + 40^{2} = 41^{2} }$

$\text{ x^{2} = 41^{2} - 40^{2} }$

$\text{ x^{2} = 1691 - 1600}$

$\text{x = \sqrt{91} }$

$\text{x = 8}$

Therefore, value of x = 8.