Question

if X 40 41 is a Pythagorean triplet what is the value of x ​

Answer 1

Solution :-

Let's :-

• Hypotenuse = 41

• Base = 40

• Perpendicular = x

By using Pythagoras theorem

⇒ H² = B² + P²

⇒ ( 41 )² = ( 40 )² + x²

⇒ 1681 = 1600 + x²

⇒ x² = 1681 - 1600

⇒ x² = 81

⇒ x = √81

⇒ x = 9

Value of x is 9