Question

If x^4x=4
Then x^2x+x^8x=?

Answer 1

Answer:

18

step by step

${x}^{4x} = 4$

taking square root on both the sides we get

$\sqrt{ {x}^{4x} } = \sqrt{4 } \\ {x}^{2x} = 2$

taking sqaures on side for given

$( {x}^{4x} ) ^{2} = 4^{2} \\ {x}^{8x} = 16$

substitute these two values in required equation, we get

${x}^{2x} + {x}^{8x} = 2 + 16 \\ = 18$