Question

If x=√(√5+1/√5-1) then the value of x^2-x-1 is

Answer 1

Answer:

$x = (1 + \sqrt{5} )$

Step-by-step explanation:

$x = ( \sqrt{5} + 1) \div ( \sqrt{5} - 1)$

ON RATIONALIZATION NUMERATOR AND DENOMINATOR , WE GET

$x = (3 + \sqrt{5} ) \div 2$

$then \: put \: \: \: \: \: x = (3 + \sqrt{5} ) \div 2 \: \: \: in \: \: \: \: \: {x}^{2} - x - 1$

WE GET ANSWER :.

$1 + \sqrt{5}$