if x = 5 - 2 root 6 find the value of x square + 1 / x square
KhushbuKuhar:
hi
Answers
Answered by
3
x=5-2√6
∴, x²=(5-2√6)²=25-2.5.2√6+24=49-20√6
1/x²=1/(5-2√6)²=1/(49-20√6)=(49+20√6)/(49-20√6)(49+20√6)=(49+20√6)/(2401-2400)=49+20√6
∴, x²+1/x²=49-20√6+49+20√6=98
Hope it's helpful to uh dear.
Thankyou.
∴, x²=(5-2√6)²=25-2.5.2√6+24=49-20√6
1/x²=1/(5-2√6)²=1/(49-20√6)=(49+20√6)/(49-20√6)(49+20√6)=(49+20√6)/(2401-2400)=49+20√6
∴, x²+1/x²=49-20√6+49+20√6=98
Hope it's helpful to uh dear.
Thankyou.
Answered by
2
☜☆☞hey friend ☜☆☞
your answer is "98"
Explanation ☞
______
=> X=5-2√6 ______given
∴, x²=(5-2√6)²
=> X² =25-2.5.2√6+24
=> X² =49-20√6
=> 1/x²=1/(5-2√6)²
=> 1/x² =1/(49-20√6)
=> 1/x² =(49+20√6)/(49-20√6)(49+20√6)
=> 1/x² =(49+20√6)/(2401-2400)
=> 1/x² =49+20√6
∴, x²+1/x²=49-20√6+49+20√6
=> x² + 1/x²=98 _____answer
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
your answer is "98"
Explanation ☞
______
=> X=5-2√6 ______given
∴, x²=(5-2√6)²
=> X² =25-2.5.2√6+24
=> X² =49-20√6
=> 1/x²=1/(5-2√6)²
=> 1/x² =1/(49-20√6)
=> 1/x² =(49+20√6)/(49-20√6)(49+20√6)
=> 1/x² =(49+20√6)/(2401-2400)
=> 1/x² =49+20√6
∴, x²+1/x²=49-20√6+49+20√6
=> x² + 1/x²=98 _____answer
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
Similar questions