Question

if X= √5+√6 , then (x²+1/x²-2) =

answer fast please​

Answer 1

Answer:

x^2+1/x^2-2

=(x)^2-2.x.1/x+(1/x)^2

=(x-1/x)^2

x=√5+√6

1/x=1/(√5+√6)

=(√5-√6)/(√5+√6)(√5-√6)

=(√5-√6)/(5-6)

=(√5-√6)/-1

=√6-√5

so,

(x-1/x)^2

={(√5+√6)-(√6-√5)}^2

=(√5+√6-√6+√5)^2

=(2√5)^2

=4×5

=20