if x=5 cos theta and y=5÷cosec theta then x^2+y^2=
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4
let theta be A for simplicity
x=5cosA
y=5/cosecA
we know that,
cosecA=1/SinA
y=5sinA
x²+y²=(5cosA)²+(5sinA)²
x²+y²=25cos²A+25sin²A
x²+y²=25(cos²A+sin²A)
x²+y²=25(1)................................(sin²A+cos²A=1)
x²+y²=25
thus, 25 is your answer
.
Answered by
0
Answer:
x=5cosθ,
y=5/cosecθ=5sinθ. (since, 1/cosecθ=sinθ)
so,x²+y²=(5cosθ)²+(5sinθ)²
=25cos²θ+25sin²θ
=25(cos²θ+sin²θ)
=25. (since,cos²θ+sin²θ=1)
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