Math, asked by rajveersin1947, 6 hours ago

if x=5 , find the value of 2x³-4x²-6x+25​

Answers

Answered by ruvvasarathchandra
0

Answer:

f(x)=2x^3-4x^2-6x+25

substitute x=5

2(5)^3-4(5)^2-6(5)+25

250-100+25-24=150+1=151

Answered by Adityasingh1604
0

Answer:

2×5^3 -4×5^2-6×5+25

2×125-4×25-30+25

250-100-30+25

150-30+25

120+25

95

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