if x=5 , find the value of 2x³-4x²-6x+25
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0
Answer:
f(x)=2x^3-4x^2-6x+25
substitute x=5
2(5)^3-4(5)^2-6(5)+25
250-100+25-24=150+1=151
Answered by
0
Answer:
2×5^3 -4×5^2-6×5+25
2×125-4×25-30+25
250-100-30+25
150-30+25
120+25
95
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