If (x + 5) is a zero of x^3 + 2x^2 – 14x + K + 2, then find K.
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Answered by
4
Answer:
Step-by-step explanation:
x+5=0
=> x= -5...........
x^3+2x^2-14x+k
=> (-5)^3+2(-5)^2-14(-5)+k+2
=> -125+50+70+k=-2
=> -5+k=-2
=> k=5-2
=> k=3........
qk321675:
what i had left
Answered by
1
Step-by-step explanation:
x+5=0
x=-5
substitue value of x
x^3+2x^2-14x+k+2
(-5)^3+2.(-5)^2-14.(-5)+k+2=0
-125+ 50+70+2+k=0
-125+122=-k
-3=-k
k=3
ans k=3
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