Math, asked by manjari24405, 1 year ago

If (x + 5) is a zero of x^3 + 2x^2 – 14x + K + 2, then find K.​

Answers

Answered by qk321675
4

Answer:

Step-by-step explanation:

x+5=0

=> x= -5...........

x^3+2x^2-14x+k

=> (-5)^3+2(-5)^2-14(-5)+k+2

=> -125+50+70+k=-2

=> -5+k=-2

=> k=5-2

=> k=3........


qk321675: what i had left
yusra174: +2
qk321675: oh my god
qk321675: i did a silly mistake
qk321675: i will edit it
yusra174: answer is e
yusra174: answer is 3
qk321675: i have edited pls see
manjari24405: yah..thanks alot to both of u...
qk321675: welcome
Answered by yusra174
1

Step-by-step explanation:

x+5=0

x=-5

substitue value of x

x^3+2x^2-14x+k+2

(-5)^3+2.(-5)^2-14.(-5)+k+2=0

-125+ 50+70+2+k=0

-125+122=-k

-3=-k

k=3

ans k=3


manjari24405: thanks dear...but 5^3= 125...
yusra174: yeah i did that
yusra174: see i edited it
manjari24405: thanks...
yusra174: welcome
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