Question

If x= √ 6 + √ 6 + √ 6 + √6 + ⋯ … … … . . and x is a natural number ,

then find the quadratic equation.​

Answer 1

X squar = underroot 6 x X

Answer 2

Answer:

$S^{2} - S - 6$

Step-by-step explanation:

I think you meant this :-

$\sqrt{6\sqrt{6\sqrt{6} } }.....$

Let this expression be equal to S ;

Square S You will realize the expression obtained is S + 6 which is basically

$S^{2} =6 + S$

Shift the terms ;

$S^{2} - S - 6$ (which is your answer)