Math, asked by abhinavkr1538, 1 month ago

if x=6,y=-2 and z=3,evaluate
x+y

xy+z
x+2y

Answers

Answered by atharvapandey1206
0

Answer:

8

36

15

10

Step-by-step explanation:

we put the value 6+2

6×6

6×2+3

6+2×2

Answered by steffiaspinno
0

1. x+y  = 4

2. x²  = 36

3. xy+z  = -9

4. x+2y = 2

Explanation:

Given:

1. x=6

2. y =-2

3. z=3

To find:

1. x+y

2. x²

3. xy+z

4. x+2y

1. x+y

==> x =6

==> y =-2

==> Substitute these values in x+y

==> x+y = 6-2

==> x+y = 4

2. x²

==> x =6

==> Substitute these values in x²

==> x² = 6²

==> = 36

3. xy+z

==> x =6

==> y =-2

==> z = 3

==> Substitute these values in xy+z

==> xy+z = 6(-2)+3

==> xy+z = -12+3

==> xy+z = -9

4. x+2y

==> x =6

==> y =-2

==> Substitute these values in x+2y

==> x+2y = 6+2(-2)

==> x+2y = 6-4

==> x+2y = 2

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