Question

If `x=(6ab)/(a+b)` find the value of ` (x+3a)/(x-3a)+(x+3b)/(x-3b) `

Answer 1

Hi mate.

ANSWER:

Given that,

$= > x = \frac{6ab}{a + b}$

$= > \frac{x + 3a}{x - 3a} + \frac{x + 3b}{x - 3b}$

$= > \frac{(x - 3b) \times(x + 3a) + (x - 3a) \times ( \times + 3b) }{(x - 3a) \times (x - 3b) }$

$\frac{ {x}^{2} + 3ax - 3bx - 9ab + {x}^{2} + 3bx - 3ax - 9ab}{ {x}^{2} - 3bx - 3ax + 9ab}$

$= > > > > > > > \frac{2 {x}^{2} - 18ab}{ {x}^{2} - 3bx - 3ax + 9ab}$

I hope you are happy.

So please mark my answer as brainlist answer...