If X = {6n - 5n - 1 | n ∈ N} and Y = {25(n - 1) | n ∈ N} then ____. a. X=Y B. X ∩ Y = ϕ C.X⊂Y D.Y⊂X
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X = { n-1 | n ∈ N } => X = N
Y = { 25(n-1) | n ∈ N} => Y = { y | y is a multiple of 25, y∈ N}
clearly Y ⊂ X
Y = { 25(n-1) | n ∈ N} => Y = { y | y is a multiple of 25, y∈ N}
clearly Y ⊂ X
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