Question

if x= 6t²+ 3t²+5 find the velocity and acceleration in the time interval 2 to 4 secs​

Answer 1

Answer:

S=t

3

−6

2

+3t+4

v=

dt

ds

So =3t

2

−12+3=v

again differentiate ,a=

dt

dv

6t−12=0

t=2s

v=3(2)

2

−12×2+3=−9ms

−1

Hence (D) is correct answer.